document.write( "Question 1038366: A driver took a​ day-trip driving at two different speeds. He drove 60 miles at a slower speed and 240 miles at a speed 30 miles per hour faster. If the time spent during the faster speed was twice that spent at a slower​ speed, find the two speeds during the trip. \n" ); document.write( "
Algebra.Com's Answer #653061 by Boreal(15235)\"\" \"About 
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slow speed is x mph for y hours, so the distance is xy miles=60. y=60/x
\n" ); document.write( "faster speed is (x+30)mph for 2y hours, so the distance is 2xy+60y miles=240, y(2x+60)=240, y=240/(2x+60)
\n" ); document.write( "Set the y's equal
\n" ); document.write( "60/x=240/(2x+60)
\n" ); document.write( "cross multiply
\n" ); document.write( "120x+3600=240x
\n" ); document.write( "120x=3600
\n" ); document.write( "x=30 mph
\n" ); document.write( "2 hours to go 60 miles, so y = 2
\n" ); document.write( "x+30 mph=60 mph. For 4 hours (2 more), and that is 240 miles
\n" ); document.write( "That checks.
\n" ); document.write( "The speeds were 30 and 60 mph.\r
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