document.write( "Question 89972: solve by using the quadratic formula\r
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Algebra.Com's Answer #65306 by uksraj(9)\"\" \"About 
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x^2+x-2=0\r
\n" ); document.write( "\n" ); document.write( "the standard form of quadratic equation is
\n" ); document.write( "ax^2+bx+c=0
\n" ); document.write( "comparing standard form with given equation we get
\n" ); document.write( "a=1; b=1 & c=-2\r
\n" ); document.write( "\n" ); document.write( "the standard solution is\r
\n" ); document.write( "\n" ); document.write( "Solution by SOLVE quadratic equation with variable
\n" ); document.write( "Quadratic equation (in our case ) has the following solutons:\r
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\n" ); document.write( "\n" ); document.write( "For these solutions to exist, the discriminant should not be a negative number.\r
\n" ); document.write( "\n" ); document.write( "First, we need to compute the discriminant : .\r
\n" ); document.write( "\n" ); document.write( "Discriminant d=9 is greater than zero. That means that there are two solutions: .\r
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\n" ); document.write( "\n" ); document.write( "Quadratic expression can be factored:\r
\n" ); document.write( "\n" ); document.write( "Again, the answer is: 2, -1. Here's your graph:
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\n" ); document.write( "\n" ); document.write( "by factorisation
\n" ); document.write( "x^2+2x-x-2=0
\n" ); document.write( "x(x+2)-1(x+2)=0
\n" ); document.write( "(x-1)(x+2)=0
\n" ); document.write( "x=1
\n" ); document.write( "x=-2
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