document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038361>Question 1038361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what are the length and width of a rectangle if the width is 27 feet less than its length, and the perimeter is 395 feet?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #653049 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=653049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width=w<BR>\n" );
document.write( "length=w+27<BR>\n" );
document.write( "perimeter is 2L+2w=395<BR>\n" );
document.write( "2(w+27)+2w=395<BR>\n" );
document.write( "4w+54=395<BR>\n" );
document.write( "4w=341<BR>\n" );
document.write( "w=85.25 feet<BR>\n" );
document.write( "l=112.25 feet<BR>\n" );
document.write( "Their sum is 197.5<BR>\n" );
document.write( "double that is 395 </SPAN>\n" );
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