document.write( "Question 89935: 44. Geometry. The length of a rectangular playing field is 5 ft less than twice its width.
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document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field. \n" );
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Algebra.Com's Answer #65300 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " . The length of a rectangular playing field is 5 ft less than twice its width. \n" ); document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field\r \n" ); document.write( "\n" ); document.write( " Let the width of the rectanglular field be = x ft \n" ); document.write( " Then length of the rectanglular field = 2x-5 ft \n" ); document.write( " perimeter of the field is = 230 ft \n" ); document.write( " perimeter = 2(length+width) \n" ); document.write( " 230 = 2(2x-5+x) \n" ); document.write( " 230/2 = 3x-5 \n" ); document.write( " 115 +5 = 3x \n" ); document.write( " 120 = 3x \n" ); document.write( " 120/3 = x \n" ); document.write( " x = 40 ft \n" ); document.write( " width of the rectangular field = 40 ft \n" ); document.write( " Length of the rectangular field = 75 ft (2*40-5= 80-5=75) \n" ); document.write( " \n" ); document.write( " |