document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038277>Question 1038277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular room has a floor surface area of 400&#960; square feet. What is the radius of the circular floor? Show your work. What is the circumference of the circular floor? Show your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652974 by </B><A HREF=/tutors/aboutme.mpl?userid=Othel><B>Othel(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Othel><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know that the area of a circle is defined as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+pi+%2A+r%5E2 ALIGN=MIDDLE  ALT=\"A+=+pi+%2A+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Since we already have the area, and need to determine the radius, we just use a little algebra. \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2Fpi+=+r%5E2 ALIGN=MIDDLE  ALT=\"A%2Fpi+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28A%2Fpi%29+=+r ALIGN=MIDDLE  ALT=\"sqrt%28A%2Fpi%29+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" >,  since we know that the radius is positive, we do not need to take the positive and negative of r, only the positive. So the radius is...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28400%29%2Fsqrt%28pi%29+=+r ALIGN=MIDDLE  ALT=\"sqrt%28400%29%2Fsqrt%28pi%29+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "and then...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2820%2F%28sqrt%28pi%29%29%29+=+r ALIGN=MIDDLE  ALT=\"%2820%2F%28sqrt%28pi%29%29%29+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Approximately 11.3 rounded to the tenths\r<BR>\n" );
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document.write( "And the circumference of the floor is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2Ar ALIGN=MIDDLE  ALT=\"2%2Api%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "which is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2A%2820%2F%28sqrt%28pi%29%29%29 ALIGN=MIDDLE  ALT=\"2%2Api%2A%2820%2F%28sqrt%28pi%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "so...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40%2Api%2F%28sqrt%28pi%29%29 ALIGN=MIDDLE  ALT=\"40%2Api%2F%28sqrt%28pi%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "which is approximately 70.9 rounded to the tenth\r<BR>\n" );
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document.write( "I hope this helps! Learn on </SPAN>\n" );
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