document.write( "Question 1038242: Roberto invested some money at 8%, and then invested $2000 more than twice this amount at 9%. His total annual income from the two investments was $3560. How much was invested at 9%?\r
\n" ); document.write( "\n" ); document.write( "The answer choices are A)$28,000 B)$2,800 C)$26,000 D)$6,000\r
\n" ); document.write( "\n" ); document.write( "I can never remember where to plug in which numbers. Could you please help me solve this?
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Algebra.Com's Answer #652952 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Let n be the amount invested at 8%. Then
\n" ); document.write( ".08n+.09(2n+2000)=3560
\n" ); document.write( ".08n+.18n+180=3560
\n" ); document.write( ".26n=3380
\n" ); document.write( "n=3380/.26=$13000 invested at 8%, $28000 invested at 9%!!!!!!!!!!!!
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