document.write( "Question 1038242: Roberto invested some money at 8%, and then invested $2000 more than twice this amount at 9%. His total annual income from the two investments was $3560. How much was invested at 9%?\r
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document.write( "The answer choices are A)$28,000 B)$2,800 C)$26,000 D)$6,000\r
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document.write( "I can never remember where to plug in which numbers. Could you please help me solve this? \n" );
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Algebra.Com's Answer #652952 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount invested at 8%. Then \n" ); document.write( ".08n+.09(2n+2000)=3560 \n" ); document.write( ".08n+.18n+180=3560 \n" ); document.write( ".26n=3380 \n" ); document.write( "n=3380/.26=$13000 invested at 8%, $28000 invested at 9%!!!!!!!!!!!! \n" ); document.write( " |