document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038212>Question 1038212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do i solve this\r<BR>\n" );
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document.write( "(x+2) squared =3(x+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652919 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+2)^2 = x^2 + 4x + 4\r<BR>\n" );
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document.write( "3*(x+2) = 3x + 6\r<BR>\n" );
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document.write( "your equation of (x+2)^2 = 3(x+2) becomes x^2 + 4x + 4 = 3x + 6\r<BR>\n" );
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document.write( "subtract 3x and 6 from both sides of the equation to get x^2 + 4x + 4 - 3x - 6 = 0\r<BR>\n" );
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document.write( "combine like terms to get x^2 + x - 2 = 0\r<BR>\n" );
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document.write( "factor this equation to get (x-1) * (x+2) = 0\r<BR>\n" );
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document.write( "solve for x to get -2 or x = 1.\r<BR>\n" );
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document.write( "those are your solutions.\r<BR>\n" );
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document.write( "to confirm they are applicable to the problem, replace x with 2 and then replace x with -1 in the original equations.\r<BR>\n" );
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document.write( "the original equation is (x+2)^2 = 3(x+2)\r<BR>\n" );
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document.write( "when x = -2, this equation becomes 0 = 0.\r<BR>\n" );
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document.write( "when x = 1, this equation becomes 9 = 9.\r<BR>\n" );
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document.write( "this confirms both solutions are correct.\r<BR>\n" );
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