document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038173>Question 1038173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Janice is thinking of two numbers. She says that two times the first number plus the second number is 48. In addition, the first number plus three times the second number is 54 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652889 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652889\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Janice is thinking of two numbers. She says that two times the first number plus the second number is 48. In addition, the first number plus three times the second number is 54 <BR>\n" );
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document.write( "Equations::<BR>\n" );
document.write( "2f + s = 48<BR>\n" );
document.write( "f + 3s = 54<BR>\n" );
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document.write( "Modify for elimination:<BR>\n" );
document.write( "2f + s = 48<BR>\n" );
document.write( "2f + 6s = 108<BR>\n" );
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document.write( "Subtract and solve for \"s\"::<BR>\n" );
document.write( "5s = 60<BR>\n" );
document.write( "second number = 12<BR>\n" );
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document.write( "Solve for \"f\"::<BR>\n" );
document.write( "f + 3s = 54<BR>\n" );
document.write( "f + 3*12 = 54<BR>\n" );
document.write( "first = 18<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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