document.write( "Question 1038120: solve the linear system using substitution\r
\n" ); document.write( "\n" ); document.write( "4x+3y=-5
\n" ); document.write( "x=y-3\r
\n" ); document.write( "\n" ); document.write( "please help fast I have a math exam tmr
\n" ); document.write( "

Algebra.Com's Answer #652821 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
Eqn #1: 4x+3y=-5
\n" ); document.write( "Eqn #2: x=y-3
\n" ); document.write( "-----------------
\n" ); document.write( "\"Substitute\" the value for x given in Eqn #2 into Eqn #1:
\n" ); document.write( "\"4x%2B3y=-5\"
\n" ); document.write( "\"4%28y-3%29%2B3y=-5\"
\n" ); document.write( "Solve for y:
\n" ); document.write( "\"4y-12%2B3y=-5\"
\n" ); document.write( "\"7y-12=-5\"
\n" ); document.write( "\"7y=7\"
\n" ); document.write( "\"highlight%28y=1%29\"
\n" ); document.write( "Now plug this result into Eqn. #2 to find x. I'll leave that part to you.
\n" ); document.write( "=======================
\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com
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