document.write( "Question 1038067: Ann, Bob, Chris, Dave and Eddy are in a group, how many ways can they be arranged in a row if Ann has to be to the left of Bob but not necessarily beside him.
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Algebra.Com's Answer #652813 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We can choose the pair of positions for A and B to be in\r\n" );
document.write( "in 5C2 = 10 ways.  In each of those 10 ways we can always\r\n" );
document.write( "put Ann left of Bob.  To illustrate, we could have Ann\r\n" );
document.write( "and Bob in any of the following 5C2 = 10 ways, with Ann\r\n" );
document.write( "always left of Bob, but not necessarily beside him.\r\n" );
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document.write( " 1.  A B _ _ _\r\n" );
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document.write( " 2.  A _ B _ _\r\n" );
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document.write( " 3.  A _ _ B _\r\n" );
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document.write( " 4.  A _ _ _ B\r\n" );
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document.write( " 5. _ A B _ _\r\n" );
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document.write( " 6. _ A _ B _\r\n" );
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document.write( " 7. _ A _ _ B\r\n" );
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document.write( " 8. _ _ A B _\r\n" );
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document.write( " 9. _ _ A _ B\r\n" );
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document.write( "10. _ _ _ A B\r\n" );
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document.write( "Then for each of those 5C2 = 10 ways to place Ann and Bob, \r\n" );
document.write( "the remaining 3 people can be arranged in the 3 blanks in \r\n" );
document.write( "3! or 6 ways:\r\n" );
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document.write( "Answer: (5C2)(3!) = (10)(6) = 60 ways.\r\n" );
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document.write( "Edwin
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