document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038097>Question 1038097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A andB together can do a piece of work in 15days . IfA's one day work is 3/2 times one days work of B. Find in how many days can each do the work.?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652794 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A and B together can do a piece of work in 15days . If A's one day work is 3/2 times one days work of B. Find in how many days can each do the work.?<BR>\n" );
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document.write( "Let B's time to do the job alone be \"x\", <BR>\n" );
document.write( "then A does the job in x/(3/2) = 2x/3 days<BR>\n" );
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document.write( "Together rate:: 1/15 job/hr<BR>\n" );
document.write( "A's rate:: 1/(2x/3) = 3/(2x) job/hr<BR>\n" );
document.write( "B's rate:: 1/x job/hr<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "rate + rate = together rate<BR>\n" );
document.write( "1/x + 3/(2x) = 1/15<BR>\n" );
document.write( "30 + 45 = 2x<BR>\n" );
document.write( "x = 75/2 = 37.5 days (time for B to do the job alone)<BR>\n" );
document.write( "2x/3 = (2/3)(37.5) = 25 days (time for A to do the job alone)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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