document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1003141>Question 1003141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During dinner the guests were told to share dishes with one another. Every 2 of them share a dish of rice, 3 for a dish of broth, every 4 for a dish for meat. If there are 65 dishes in all how many guests were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652739 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the number of dinner guests. Then:<BR>\n" );
document.write( "n/2+n/3+n/4=65<BR>\n" );
document.write( "6n+4n+3n=780<BR>\n" );
document.write( "13n=780<BR>\n" );
document.write( "n=60<BR>\n" );
document.write( "There were 60 guests!!!!!!!!!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );