document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1038034>Question 1038034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two ships leave a port, sailing at 16 km/h and 12 km/h. The angle between their directions of travel from the port is 40°. How far apart are the ships after 3 hours? Include a diagram.\r<BR>\n" );
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document.write( "16(3) = 48<BR>\n" );
document.write( "18(3) = 54\r<BR>\n" );
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document.write( "c^2 = 48^2+54^2-2(48)(54)cos40°<BR>\n" );
document.write( "c^2 = 2304+2916-5184(cos40°)<BR>\n" );
document.write( "c^2 = 5220-3971.17<BR>\n" );
document.write( "c = 1248.83 km\r<BR>\n" );
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document.write( "I believe I have the answer right but I am having trouble with sketching the diagram correctly. Help would be appreciated.<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652716 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> =======+<BR>\n" );
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document.write( "Scalene triangle, but the distance can't be that large, for the ships, even if going in opposite directions would be only 84 km apart at 3 hours.  The 1248.83 number is for c^2; the square root is 35.34 km. </SPAN>\n" );
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