document.write( "Question 1037991: The question I have is \"Describe how the graph of f(x)=-1/4(x-5)^2 is related to the graph of f(x)=x^2.\"\r
\n" ); document.write( "\n" ); document.write( "I don't need the answer, I have that! \r
\n" ); document.write( "\n" ); document.write( "I have a math final tomorrow and this just a study guide question.
\n" ); document.write( " I need to know HOW my teacher got \"curves down,wider,shifts 5 units right.\" Thank you! \n" ); document.write( "

Algebra.Com's Answer #652664 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
You are hopefully familiar with the parabola shape y=x^2.\r
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\n" ); document.write( "\n" ); document.write( "Adding or subtracting to the variable moves the graph left or right, that number of units. $\"%28x-5%29%5E2\"$ is movement five units to the right.\r
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\n" ); document.write( "\n" ); document.write( " $\"%281%2F4%29%28x-5%29%5E2\"$ cuts the size of each function value by factor of $\"1%2F4\"$ . For example, the value which WAS 16 in $\"x%5E2\"$ becomes (1/4)*16=4 when you have the function as $\"%281%2F4%29%28x-5%29%5E2\"$ .\r
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\n" ); document.write( "\n" ); document.write( "The negative coefficient instead of the positive coefficient reflects the graph through the x-axis. $\"-%281%2F4%29%28x-5%29%5E2\"$ makes what was positive become negative, and what was negative become positive. Notice that $\"%281%2F4%29%28x-5%29%5E2\"$ has no negative values; but $\"-%281%2F4%29%28x-5%29%5E2\"$ will have NO positive values - only negative values and 0. \n" ); document.write( "

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