document.write( "Question 89839: Solve the following equation for Y: (square root of)2Y+ 3= 11 \n" ); document.write( "

Algebra.Com's Answer #65260 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Solve the following equation for Y: (square root of)2Y+ 3= 11
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\n" ); document.write( " $\"sqrt%282y%29\"$ + 3 = 11
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\n" ); document.write( " $\"sqrt%282y%29\"$ = 11 - 3
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\n" ); document.write( " $\"sqrt%282y%29\"$ = 8
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\n" ); document.write( "Square both sides and you have:
\n" ); document.write( "2y = 64
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\n" ); document.write( "y = 64/2
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\n" ); document.write( "y = 32
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\n" ); document.write( "Check solution:
\n" ); document.write( " $\"sqrt%282%2A32%29\"$ + 3 = 11
\n" ); document.write( " $\"sqrt%2864%29\"$ + 3 = 11 \n" ); document.write( "

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