document.write( "Question 1037252: The parabola has a turning point at (z, -8). It intersects the y-axis at y=10 and one of the x-intercepts is x=5. Find:
\n" ); document.write( "the value of z
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Algebra.Com's Answer #652592 by robertb(5830)\"\" \"About 
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Let the quadratic function be \"f%28x%29+=+a%28x-r%29%28x-5%29\", where x=5 is one of the roots (as given via the x-intercept), and x = r is the other root.\r
\n" ); document.write( "\n" ); document.write( "Since y = 10 is the value of the y-intercept, the constant term in the quadratic function must be equal to 5ar, and moreover, 5ar = 10, by hypothesis.\r
\n" ); document.write( "\n" ); document.write( "==> ar = 2.\r
\n" ); document.write( "\n" ); document.write( "Since the turning point (or the vertex of the parabola) is always midway between the two roots, it follows that \"z+=+%28r%2B5%29%2F2\".\r
\n" ); document.write( "\n" ); document.write( "==> , or
\n" ); document.write( "\"a%28r-5%29%5E2+=+32\".
\n" ); document.write( "Divide this equation by the equation ar = 2, giving\r
\n" ); document.write( "\n" ); document.write( "\"%28r-5%29%5E2%2Fr+=+16\", or,
\n" ); document.write( "\"%28r-5%29%5E2+=+16r\" or
\n" ); document.write( "\"r%5E2-26r%2B25+=+%28r-25%29%28r-1%29+=+0\", after expanding and simplifying.\r
\n" ); document.write( "\n" ); document.write( "==> r = 25 or r = 1.
\n" ); document.write( "If r = 25, then a = 2/25.
\n" ); document.write( "If r = 1, then a = 2.\r
\n" ); document.write( "\n" ); document.write( "Hence there are two possible answers:
\n" ); document.write( "(i) The function \"f%28x%29+=+%282%2F25%29%28x-25%29%28x-5%29\" has \"z+=+%2825%2B5%29%2F2+=+15\", while,
\n" ); document.write( "(ii) The function \"f%28x%29+=+2%28x-1%29%28x-5%29\" has \"z+=+%281%2B5%29%2F2+=+3\".
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