document.write( "Question 1037530: Ajax is 8km due west of Oshawa. Uxbridge is 16 km NW of Oshawa. How far is it from Ajax to Uxbridge? Explain whether you have enough information to solve this problem? \n" ); document.write( "
| Algebra.Com's Answer #652491 by ankor@dixie-net.com(22740)     You can put this solution on YOUR website! Ajax is 8km due west of Oshawa. \n" ); document.write( " Uxbridge is 16 km NW of Oshawa. \n" ); document.write( " How far is it from Ajax to Uxbridge? \n" ); document.write( ": \n" ); document.write( "One interior angle formed by the NW line to Ux is 45 degrees, therefore: \n" ); document.write( "You can use the law of cosines: a^2 = b^2 + c^2 - 2bc*cos(A) \n" ); document.write( "Where \n" ); document.write( "A = 45 degrees, \n" ); document.write( "a = dist from Ux to Aj \n" ); document.write( "b = 8 \n" ); document.write( "c = 16 \n" ); document.write( "a^2 = 8^2 + 16^2 - 2*8*16*cos(45) \n" ); document.write( "a^2 = 64 + 256 - 256(.707) \n" ); document.write( "Do the math \n" ); document.write( "a = \n" ); document.write( "a = 11.8 km from Aj to Ux \n" ); document.write( " \n" ); document.write( " |