document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89878>Question 89878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When my professor explains this I understand.  When I get home, it is like written in Hebrew or something.  Can you please explain to me (in detail) how to solve a problem like this?  I am trying to solve for (x,y,z).  My final in is tomorrow and I need to know this stuff.  Thanks in advance.  \r<BR>\n" );
document.write( "\n" );
document.write( "x+y+2z=11<BR>\n" );
document.write( "x+y+3z=14<BR>\n" );
document.write( "x+2y-z=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65240 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y+2z=11 now subtract the second equation:<BR>\n" );
document.write( "-(x+y+3z=14)<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "-z=-3 or z=3 answer.<BR>\n" );
document.write( "x+2y-3=5 now subtract the first equation after replacing z by 3:<BR>\n" );
document.write( "-(x+y+2*3=11)<BR>\n" );
document.write( "-----------------------------------<BR>\n" );
document.write( "y-3+6=-6<BR>\n" );
document.write( "y-3=0<BR>\n" );
document.write( "y=3 answer.<BR>\n" );
document.write( "x+3+2*3=11<BR>\n" );
document.write( "x+3+6=11<BR>\n" );
document.write( "x+9=11<BR>\n" );
document.write( "x=11-9<BR>\n" );
document.write( "x=2 answer.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );