document.write( "Question 1037716: To be the top 3% of the
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\n" ); document.write( "you need if the mean must be 70% and standard
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Algebra.Com's Answer #652342 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Look up the standard normal (Z) score that corresponds to 97%. Multiply that Z-score by the standard deviation and then add the result to the mean. Anything at or above that number is in the top 3%.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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