document.write( "Question 1037678: In the process of making a sphere out of marble, the first step is to cut the rough piece of marble into a cube. After this, rough cuts are made to get rid of as many corners as possible. Then, the sculptor grinds away any sharp edges. The result is a roundish piece of rock that is put into another grinding machine that has two cupped grinders rotating in opposite directions. \r
\n" ); document.write( "\n" ); document.write( "a. What volume of rock was in the cube if the original piece of rock was cut into a cube with side lengths of 60 mm? Round to the nearest cubic millimetre.
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\n" ); document.write( "b. What is the maximum diameter of the sphere that could be made from the cube?
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\n" ); document.write( "c. If the sphere has the maximum diameter, what is the volume of rock in the sphere at the end of the process? Round to the nearest cubic millimetre.
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\n" ); document.write( "\n" ); document.write( "d. How much rock was cut or ground away?
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Algebra.Com's Answer #652338 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In the process of making a sphere out of marble, the first step is to cut the rough piece of marble into a cube. After this, rough cuts are made to get rid of as many corners as possible. Then, the sculptor grinds away any sharp edges. The result is a roundish piece of rock that is put into another grinding machine that has two cupped grinders rotating in opposite directions.
\n" ); document.write( "a. What volume of rock was in the cube if the original piece of rock was cut into a cube with side lengths of 60 mm? Round to the nearest cubic millimetre.
\n" ); document.write( "Ans: 60^3 = 216000 mm^3
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\n" ); document.write( "\n" ); document.write( "b. What is the maximum diameter of the sphere that could be made from the cube?
\n" ); document.write( "Ans: 60mm
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\n" ); document.write( "\n" ); document.write( "c. If the sphere has the maximum diameter, what is the volume of rock in the sphere at the end of the process? Round to the nearest cubic millimetre.
\n" ); document.write( "V = (4/3)pi*r^3
\n" ); document.write( "V = (4/3)pi*30^3 = 113,097 mm^3
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\n" ); document.write( "d. How much rock was cut or ground away?
\n" ); document.write( "216000- 113.097 = 102,903 mm^3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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