document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037646>Question 1037646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 30 cm. The length of one leg is 6 cm longer than the other leg. Find the length of the shorter leg.\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652296 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let L be the shorter leg. Then:<BR>\n" );
document.write( "L^2+(L+6)^2=30^2<BR>\n" );
document.write( "L^2+L^2+12L+36=900<BR>\n" );
document.write( "2L^2+12L-864=0<BR>\n" );
document.write( "L^2+6L-432=0<BR>\n" );
document.write( "(L+24)(L-18)=0<BR>\n" );
document.write( "L=18,-24<BR>\n" );
document.write( "The legs are 18 and 24 cms. long!!!!!!!!!! </SPAN>\n" );
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