document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037687>Question 1037687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> brandy dawson and jason dodge start a motorcycle trip at the same point. both are traveling to san antonio a distance of about 400 kilometers. brandy rides 30 kilometers per hour faster than jason does. when brandy reaches her destination, jason has only traveled to austin, texas a distance of about 250 kilometers. determine the approx. speed of each motorcycle?\r<BR>\n" );
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document.write( "identify the variables, write the equation and solve algebraically  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652292 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r=jason's rate.<BR>\n" );
document.write( "400/r+30=250/r<BR>\n" );
document.write( "250(r+30)=400r<BR>\n" );
document.write( "250r+7500=400r<BR>\n" );
document.write( "150r=7500<BR>\n" );
document.write( "r=50<BR>\n" );
document.write( "r+30=80<BR>\n" );
document.write( "Brandy is going 80 km/h, jason at 50 km/h!!!!!!!!!!!!!! </SPAN>\n" );
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