document.write( "Question 89579: x kilo of coffee worth P100 per kilo is mixed with coffee worth P90.00 per kilo to produce 200 kg of coffee worth P95 per kilo. Find x. \n" ); document.write( "

Algebra.Com's Answer #65227 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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x kilo of coffee worth P100 per kilo is mixed with coffee worth P90.00 per kilo to produce 200 kg of coffee worth P95 per kilo. Find x.
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\n" ); document.write( "Just looking at the problem, it is apparent that it would be half and half but here is a universal method, for this type of problem:
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\n" ); document.write( "Given that x = P100 coffee amt, and the resulting amt is 200 kg, we can say:
\n" ); document.write( "(200-x) = P90 coffee amt
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\n" ); document.write( "100x + 90(200-x) = 95(200)
\n" ); document.write( "100x + 18000 - 90x = 19000
\n" ); document.write( "100x - 90x = 19000 - 18000
\n" ); document.write( "10x = 1000
\n" ); document.write( "x = 1000/10
\n" ); document.write( "x = 100kg of P100 coffee
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\n" ); document.write( "Check:
\n" ); document.write( "100(100) + 90(100) = 19000
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