document.write( "Question 1037610: find the perimeter of triangle ABC where A(-4,-1) B(4,5) and C(4,-2)
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Algebra.Com's Answer #652249 by jhunjiro(67) $\"\"$ $\"About$

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To get the Perimeter you need to get the distance between two points
\n" ); document.write( "then add them\r
\n" ); document.write( "\n" ); document.write( "Perimeter of Triangle = a+b+c
\n" ); document.write( "a=AB
\n" ); document.write( "b=BC
\n" ); document.write( "c=AC
\n" ); document.write( "distance formula for two points
\n" ); document.write( " $\"d+=sqrt%28+%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "AB=sqrt((x2-x1)^2+(y2-y1)^2)
\n" ); document.write( "AB=sqrt((4--4)^2+(5--1)^2)
\n" ); document.write( "AB=sqrt(64+36)
\n" ); document.write( "AB=sqrt(100)
\n" ); document.write( "AB=10
\n" ); document.write( "-----------
\n" ); document.write( "BC=sqrt((x2-x1)^2+(y2-y1)^2)
\n" ); document.write( "=sqrt((4-4)^2+(-2-5)^2)
\n" ); document.write( "=sqrt(0+49)
\n" ); document.write( "=sqrt(49)
\n" ); document.write( "=7
\n" ); document.write( "--------------
\n" ); document.write( "AC=sqrt((x2-x1)^2+(y2-y1)^2)
\n" ); document.write( "=sqrt((4--4)^2+(-2--1)^2)
\n" ); document.write( "=sqrt(64+1)
\n" ); document.write( "=sqrt(65)
\n" ); document.write( "=8.06225774829855
\n" ); document.write( "=8.0623
\n" ); document.write( "-------------------------------\r
\n" ); document.write( "\n" ); document.write( "perimeter = 10+7+8.0623\r
\n" ); document.write( "\n" ); document.write( "P= 25.0623\r
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