document.write( "Question 1037598: Simplify:\r
\n" ); document.write( "\n" ); document.write( "sqrt45sqrt2000\r
\n" ); document.write( "\n" ); document.write( "I can solve up to:\r
\n" ); document.write( "\n" ); document.write( "sqrt45 => sqrt9*5 => 3sqrt5\r
\n" ); document.write( "\n" ); document.write( "When I get up to sqrt2000, \r
\n" ); document.write( "\n" ); document.write( "I'm having trouble in deciding what numbers to use to break it down.
\n" ); document.write( "

Algebra.Com's Answer #652204 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Simplify:
\n" ); document.write( "sqrt45sqrt2000
\n" ); document.write( "I can solve up to:
\n" ); document.write( "sqrt45 => sqrt9*5 => 3sqrt5
\n" ); document.write( "When I get up to sqrt2000,
\n" ); document.write( "I'm having trouble in deciding what numbers to use to break it down.
\n" ); document.write( "-----
\n" ); document.write( "2000 = 100*20 = 100*4*5
\n" ); document.write( "----
\n" ); document.write( "sqrt(2000) = sqrt(100*4*5) = 10*2*sqrt(5) = 20*sqrt(5)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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