document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037538>Question 1037538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular field has an area of 600 square feet. If a scale drawing of the fied has a length of 4 inches and an area of 20 square inches, what is the perimeter of the field in real life?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652153 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular field has an area of 600 square feet. If a scale drawing of the fied has a length of 4 inches and an area of 20 square inches, what is the perimeter of the field in real life? <BR>\n" );
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document.write( "Drawing is 4 by 5 inches.<BR>\n" );
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document.write( "The ratio of areas is 600*12*12/20 = 4320:1<BR>\n" );
document.write( "Area is a function of L*W --> ratio of L & W is sqrt(4320) =~ 65.73:1<BR>\n" );
document.write( "L = 4*65.73 inches = 21.91 feet<BR>\n" );
document.write( "W = 5*65.73 inches = 27.386 feet\r<BR>\n" );
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