document.write( "Question 1037457: simon has a garden that is ten feet wide with a perimeter of 50. what is the area? \n" ); document.write( "

Algebra.Com's Answer #652109 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+L+\"$ = length
\n" ); document.write( "Let $\"+W+\"$ = width
\n" ); document.write( "Perimeter = $\"+2W+%2B+2L+\"$
\n" ); document.write( " $\"+50+=+2%2A10+%2B+2L+\"$
\n" ); document.write( " $\"+2L+=+50+-+20+\"$
\n" ); document.write( " $\"+2L+=+30+\"$
\n" ); document.write( " $\"+L+=+15+\"$
\n" ); document.write( "----------------
\n" ); document.write( "Area = $\"+L%2AW+\"$
\n" ); document.write( "Area = $\"+15%2A10+\"$
\n" ); document.write( "Area = $\"+150+\"$ ft2 \n" ); document.write( "

\n" );