document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037471>Question 1037471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Johann has an antique printing press that he inherited from his grandfather.The printing press is currently worth $26 600, and it has been appreciating at a rate of 3%  each year. Use a graphical model of the problem to predict how many years will it take for the value of the printing press to double.\r<BR>\n" );
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document.write( "Thanks so much :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652105 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation you are looking for is y = 26600 * 1.03^x.\r<BR>\n" );
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document.write( "x is the number of years.\r<BR>\n" );
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document.write( "the current year is year 0.\r<BR>\n" );
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document.write( "the value when x = 0 is 26600 * 1.03^0 = 26600.<BR>\n" );
document.write( "the value when x = 1 is 26600 * 1.03^1 = 27398.\r<BR>\n" );
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document.write( "you can solve for when it will double by formula as follows:\r<BR>\n" );
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document.write( "2 * 26600 = 53200.\r<BR>\n" );
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document.write( "formula becomes 53200 = 26600 * 1.03^x.<BR>\n" );
document.write( "divide both sides of this equation by 26600 to get 2 = 1.03^x.\r<BR>\n" );
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document.write( "2 = 1.03^x is the formula you would use.<BR>\n" );
document.write( "take the log of both sides of this equation to get log(2) = log(1.03^x).<BR>\n" );
document.write( "log(1.03^x) is equivalent to x * log(1.03)<BR>\n" );
document.write( "formula becomes log(2) = x * log(1.03)<BR>\n" );
document.write( "divide both sides of the equation by log(1.03) and solve for x to get x = log(2) / log(1.03).<BR>\n" );
document.write( "your solution should be x = 23.44977225 years.\r<BR>\n" );
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document.write( "graphically, you would graph the function of y = 26600 * 1.03^2.<BR>\n" );
document.write( "you would also graph y = 53200.<BR>\n" );
document.write( "the intersection of the two equations will be the solution.\r<BR>\n" );
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document.write( "the graph looks like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2016/060704.jpg\" alt=\"$$$\" </>\r<BR>\n" );
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document.write( "the graph shows that the intersection of the two equation occurs when x = 23.45.\r<BR>\n" );
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document.write( "that's the same answer you got by formula after it is rounded to two decimal places. </SPAN>\n" );
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