document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037428>Question 1037428</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a sector of a circle with an angle of 60° has an area of 24 pi what is the radius of the circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652076 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60/360=1/6<BR>\n" );
document.write( "1/6 Area of circle=24 pi<BR>\n" );
document.write( "A=24/(1/6)=144 pi;<BR>\n" );
document.write( "pi*r^2=144 pi<BR>\n" );
document.write( "r^2=144<BR>\n" );
document.write( "r=12<BR>\n" );
document.write( "The radius is 12!!!!!!!!!!!!!!!!!<BR>\n" );
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