document.write( "Question 89773: The denominator of a certain fraction is three more than twice the numerator. If 7 are added to both terms of the fraction, the resulting fraction is 3/5. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #65207 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! The denominator of a certain fraction is three more than twice the numerator. If 7 are added to both terms of the fraction, the resulting fraction is 3/5. Find the original fraction. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( " (5)(x+7)=(3)(3x+9) [cross-multiply to simplfy] \n" ); document.write( ". \n" ); document.write( "5x+35=9x+27 [solve for the x-term] \n" ); document.write( "35=9x-5x+27 \n" ); document.write( "35=4x+27 \n" ); document.write( "35-27=4x \n" ); document.write( "8=4x \n" ); document.write( "x=2 \n" ); document.write( ". \n" ); document.write( "check by plugging (x=2) back into the original equation\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |