document.write( "Question 89773: The denominator of a certain fraction is three more than twice the numerator. If 7 are added to both terms of the fraction, the resulting fraction is 3/5. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #65207 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
The denominator of a certain fraction is three more than twice the numerator. If 7 are added to both terms of the fraction, the resulting fraction is 3/5. Find the original fraction.
\n" ); document.write( "\"%28x%2Fy%29\" = C
\n" ); document.write( "\"%28x%2F%282x%2B3%29%29\"=C
\n" ); document.write( "\"%28%28x%2B7%29%2F%28%283x%2B2%29%2B7%29%29\"=\"3%2F5%29\" [original fraction]
\n" ); document.write( "or
\n" ); document.write( " \"%28%28x%2B7%29%2F%28%283x%2B9%29%29%29\"=\"3%2F5%29\"
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( " (5)(x+7)=(3)(3x+9) [cross-multiply to simplfy]
\n" ); document.write( ".
\n" ); document.write( "5x+35=9x+27 [solve for the x-term]
\n" ); document.write( "35=9x-5x+27
\n" ); document.write( "35=4x+27
\n" ); document.write( "35-27=4x
\n" ); document.write( "8=4x
\n" ); document.write( "x=2
\n" ); document.write( ".
\n" ); document.write( "check by plugging (x=2) back into the original equation\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x%2B7%29%2F%28%283x%2B2%29%2B7%29%29\"=\"3%2F5%29\"
\n" ); document.write( "\"%28%282%2B7%29%2F%28%283%282%29%2B2%29%2B7%29%29\"=\"3%2F5%29\"
\n" ); document.write( "\"%289%2F15%29\" = \"3%2F5%29\" [reducing]
\n" ); document.write( "\"%283%2F5%29\" = \"3%2F5%29\" [checks out]\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );