document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037444>Question 1037444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve cos(3pi+pi/4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652069 by </B><A HREF=/tutors/aboutme.mpl?userid=thesvw><B>thesvw(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thesvw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thesvw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%283pi%2Bpi%2F4%29=+cos%283pi%29%2Acos%28pi%2F4%29+-+sin%283pi%29%2Asin%28pi%2F4%29 ALIGN=MIDDLE  ALT=\"cos%283pi%2Bpi%2F4%29=+cos%283pi%29%2Acos%28pi%2F4%29+-+sin%283pi%29%2Asin%28pi%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "= (-1)(1/sqrt( 2 )) - 0(1/sqrt( 2 ))\r<BR>\n" );
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document.write( "= -(1/sqrt( 2 ))\r<BR>\n" );
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document.write( "sqrt means sqare root. </SPAN>\n" );
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