document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037442>Question 1037442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy is one third the age of his father. The sum of their ages is 52. What are their ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #652063 by </B><A HREF=/tutors/aboutme.mpl?userid=thesvw><B>thesvw(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thesvw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thesvw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=652063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the father age be A. So sons age is A/3.\r<BR>\n" );
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document.write( "A + A/3 = 52\r<BR>\n" );
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document.write( "4A =156\r<BR>\n" );
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document.write( "A = 39 years. </SPAN>\n" );
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