document.write( "Question 1037398: If x+y+z=12,x2+y2+z2=64,find xy+yz+zx \n" ); document.write( "
Algebra.Com's Answer #652049 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "If x+y+z=12, x2+y2+z2=64, find xy+yz+zx
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document.write( "Use  \"%28x%2By%2Bz%29%5E2\" - \"%28x%5E2+%2B+y%5E2+%2Bz%5E2%29\" = \"2%2A%28xy%2Byz%2Bzx%29\".\r\n" );
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document.write( "It gives  \"12%5E2\" - \"64\" = \"2%2A%28xy%2Byz%2Bzx%29\",  or\r\n" );
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document.write( "\"xy%2Byz%2Bzx\" = \"%28144-64%29%2F2\" = 40.\r\n" );
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document.write( "Answer.  40.\r\n" );
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