document.write( "Question 1037369: two pipes running simultaneously can fill a tank in 2 hours and 40 minutes. after the large pipe had run for 3 hours the smaller pipe was also turned on and the tank was full 40 minutes later. how long would it take the smaller pipe to fill the tank alone? \n" ); document.write( "

Algebra.Com's Answer #652024 by josgarithmetic(39620) $\"\"$ $\"About$

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document.write( "                        RATE\r\n" );
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document.write( "BIG PIPE               \r\n" );
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document.write( "SMALL PIPE                \r\n" );
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\n" ); document.write( "\n" ); document.write( "Work was done in two time periods: three hour only big pipe, two-thirds hour both pipes.\r
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\n" ); document.write( "\n" ); document.write( " $\"%283%2F8%29%2A3%2B%283%2F8%2B1%2Fs%29%282%2F3%29=1\"$ -----------the \"1\" counting the ONE ENTIRE tank volume. Solve for s, the time for the small pipe alone to fill the one tank. \n" ); document.write( "

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