document.write( "Question 12967: Would someone please help me understand this?:
\n" ); document.write( "-2(z-4)-(3z-2)=-2-(6z-2)
\n" ); document.write( "-2z+8-3z+2=12z+4 (this is where I get confused-do I add -2z and -3z?)
\n" ); document.write( "-5z+10=12z+4?
\n" ); document.write( "+5z +5z
\n" ); document.write( "10=7z+4
\n" ); document.write( "-4 -4
\n" ); document.write( "6=7z?
\n" ); document.write( "divide both by 6?
\n" ); document.write( "Any help is appreciated-thank you
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Algebra.Com's Answer #6520 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Ok, you have:\r
\n" ); document.write( "\n" ); document.write( "\"-2%28z-4%29-%283z-2%29+=+-2-%286z-2%29\" You did the left side just fine. But on the right side, the -2 is not multiplying the (6z-2), at least, going by the way you have written it. So your second step is in error. It should be:\r
\n" ); document.write( "\n" ); document.write( "\"-2z%2B8-3z%2B2+=+-2-6z%2B2\" Collect like-terms.
\n" ); document.write( "\"-5z%2B10+=+-6z\" Add 6z to both sides.
\n" ); document.write( "\"z%2B10+=+0\" Subtract 10 from both sides.
\n" ); document.write( "\"z+=+-10\"\r
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