document.write( "Question 1037262: A kite has a string 100 m long anchored to the ground. The string makes an angle with the ground of 65 degrees. What is the horizontal distance of the kite from the anchor? \n" ); document.write( "
Algebra.Com's Answer #651955 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Consider the question as a
\n" ); document.write( "right angled triangle:
\n" ); document.write( "Length of string = hypotenuse.
\n" ); document.write( "Base of triangle = Distance
\n" ); document.write( "from anchor to below the kite.= Adjacent side
\n" ); document.write( "Height of kite above ground = Opposite side.
\n" ); document.write( "Using Trig Ratios (SOHCAHTOA)
\n" ); document.write( "Adjacent side =
\n" ); document.write( "Cos(65) = Adjacent/ Hypotenuse
\n" ); document.write( "Cos(65) = Adjacent/100
\n" ); document.write( "Adjacent = Cos(65) x 100
\n" ); document.write( "Adjacent = 42.26 m (2 decimal places)
\n" ); document.write( "Height => Sin(65) = Opposite/Hypotenuse
\n" ); document.write( "Sin(65) = Opposite/100
\n" ); document.write( "Opposite = Sin(65) x 100
\n" ); document.write( "Opposite = 90.63 m (2 decimal places)
\n" ); document.write( "Horizontal distance = 42.26 m
\n" ); document.write( "Vertical Distance = 90.63 m
\n" ); document.write( "Hope this helps :-) \n" ); document.write( "
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