document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037224>Question 1037224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square based pyramid has a volume of 1100 mm^3. It's height is 15 mm. Calculate the dimensions of the base of the pyramid. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651926 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1100 = s^2*15 where s is the sides of the base (it's a square, so it has 4 equal sides)<BR>\n" );
document.write( "1100/15 = s^2<BR>\n" );
document.write( "73.333 = s^2 NOTE: 73.333 is the square of the side of the base, meaning that 73.333 is the area of the base.<BR>\n" );
document.write( "Now take the square root, both sides:<BR>\n" );
document.write( "s = 8.563 This is the length of each side<BR>\n" );
document.write( "8.563*4 = 25 is the perimeter of the base.<BR>\n" );
document.write( "John  </SPAN>\n" );
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