document.write( "Question 1037143: A tank is 80cm in length, 50cm in width and 60cm in height. It is half filled with water. A solid cylinder with base radius 20cm and height 50cm is fully immersed in water and no water is absorbed. Find the increase of the depth of the water (pi=3.14) to 1dp.\r
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Algebra.Com's Answer #651862 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "A tank is 80 cm in length, 50 cm in width and 60 cm in height. It is half filled with water.
\n" ); document.write( "A solid cylinder with base radius 20 cm and height 50 cm is fully immersed in water and no water is absorbed.
\n" ); document.write( "Find the increase of the depth of the water (pi=3.14) to 1 dp.
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document.write( "The volume of the water in the tank (before immersing) is \r\n" );
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document.write( " =  = 80*50*(60/2) ,   where h = 30 cm =  cm is the water level before immersing.\r\n" );
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document.write( "Let H be the water height after immersing. The volume of water didn't change, so we have this equation\r\n" );
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document.write( "80*50*30 = , where r and  are dimensions of the cylinder.\r\n" );
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document.write( "Divide both sides by 80*50 and get\r\n" );
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document.write( "H = 30 + .\r\n" );
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document.write( "You make calcs.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See also a similar solved problem in \r
\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/Volume/Volume.faq.question.1036906.html \r
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