document.write( "Question 1037120: A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water. How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water? \n" ); document.write( "
Algebra.Com's Answer #651836 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water. \n" ); document.write( " How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water? \n" ); document.write( ": \n" ); document.write( "the first mixture, contains a total of 16+8 = 24 liters \n" ); document.write( " it will be 16/24 or 2/3 milk \n" ); document.write( "the second mixture, contains a total of 16+5 = 21 liters \n" ); document.write( " it will be 16/21 milk \n" ); document.write( "the resulting mixture will be a total of 20+8 = 28 liters \n" ); document.write( " it will be 20/28 or 5/7 milk \n" ); document.write( ": \n" ); document.write( "let a = amt of the 1st mixture required \n" ); document.write( "the resulting mixture will have 20 liters, therefore \n" ); document.write( "(20 - a) = amt of the 2nd mixture required \n" ); document.write( ": \n" ); document.write( "A mixture equation \n" ); document.write( " \n" ); document.write( "multiply by 21, cancel the denominators, and you have \n" ); document.write( "7(2a) + 16(20-a) = 3(5(20)) \n" ); document.write( "14a + 320 - 16a = 300 \n" ); document.write( "14a - 16a = 300 - 320 \n" ); document.write( "-2a = -20 \n" ); document.write( "a = -20/-2 \n" ); document.write( "a = +10 liters of mixture 1 \n" ); document.write( "then \n" ); document.write( "20 - 10 = 10 liters of mixture 2 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this out, see if the amt of water checks out \n" ); document.write( "A is 1/3 water or 3.33 liters \n" ); document.write( "B is 5/21 water or 2.38 liters\ \n" ); document.write( "------------------------------------ \n" ); document.write( "resulting amt has 2/7 water or 5.71 liters, the sum. \n" ); document.write( " \n" ); document.write( " |