document.write( "Question 1037120: A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water. How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water? \n" ); document.write( "
Algebra.Com's Answer #651836 by ankor@dixie-net.com(22740)\"\" \"About 
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A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water.
\n" ); document.write( " How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water?
\n" ); document.write( ":
\n" ); document.write( "the first mixture, contains a total of 16+8 = 24 liters
\n" ); document.write( " it will be 16/24 or 2/3 milk
\n" ); document.write( "the second mixture, contains a total of 16+5 = 21 liters
\n" ); document.write( " it will be 16/21 milk
\n" ); document.write( "the resulting mixture will be a total of 20+8 = 28 liters
\n" ); document.write( " it will be 20/28 or 5/7 milk
\n" ); document.write( ":
\n" ); document.write( "let a = amt of the 1st mixture required
\n" ); document.write( "the resulting mixture will have 20 liters, therefore
\n" ); document.write( "(20 - a) = amt of the 2nd mixture required
\n" ); document.write( ":
\n" ); document.write( "A mixture equation
\n" ); document.write( "\"2%2F3\"a + \"16%2F21\"(20 - a) = \"5%2F7\"(20)
\n" ); document.write( "multiply by 21, cancel the denominators, and you have
\n" ); document.write( "7(2a) + 16(20-a) = 3(5(20))
\n" ); document.write( "14a + 320 - 16a = 300
\n" ); document.write( "14a - 16a = 300 - 320
\n" ); document.write( "-2a = -20
\n" ); document.write( "a = -20/-2
\n" ); document.write( "a = +10 liters of mixture 1
\n" ); document.write( "then
\n" ); document.write( "20 - 10 = 10 liters of mixture 2
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this out, see if the amt of water checks out
\n" ); document.write( "A is 1/3 water or 3.33 liters
\n" ); document.write( "B is 5/21 water or 2.38 liters\
\n" ); document.write( "------------------------------------
\n" ); document.write( "resulting amt has 2/7 water or 5.71 liters, the sum.
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