document.write( "Question 1037120: A vessel contains a mixture of 16 litres of milk and 8 litres of water and a second vessel contains a mixture of 16 litres of milk and 5 litres of water. How much of the mixture of milk and water should be taken from the first and the second vessels respectively and placed in a third vessel, so that the third vessel may contain a mixture of 20 litres of milk and 8 litres of water? \n" ); document.write( "

Algebra.Com's Answer #651835 by jorel555(1290) $\"\"$ $\"About$

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If the first vessel is 16 litres of milk to 8 litres of water, then it is 16/24 milk, or .67 milk. Similarly, the second mix is 16/21 milk, or .762 milk. We want 20 litres of mile out of 28. Let n= amount of first mixture. Then:
\n" ); document.write( ".67n+.762(28-n)=20
\n" ); document.write( ".67n+21.336-.762n=20
\n" ); document.write( ".092n=1.336
\n" ); document.write( "n=1.336/.092=14.52 litres of the first mixture, and 13.47 litres of the second!!!!!!!!!!!!!
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