document.write( "Question 1037109: The solution of the following linear system is (13/5 , 1/5). Solve for the values of A and B. Show your work.
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Algebra.Com's Answer #651820 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "The solution of the following linear system is (13/5 , 1/5). Solve for the values of A and B. Show your work.
\n" ); document.write( "Ax+By=15
\n" ); document.write( "Bx-Ay=25 \r
\n" ); document.write( "\n" ); document.write( "Thanks!
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document.write( "1.  Substitute (plug-in)  \"13%2F5\" instead of  x  and  \"1%2F5\"  instead of y. Uoi will get\r\n" );
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document.write( "    \"A%2A%2813%2F5%29\" + \"B%2A%281%2F5%29\" = 15,     (1)\r\n" );
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document.write( "    \"B%2A%2813%2F5%29\" - \"A%2A%281%2F5%29\" = 25.     (2)\r\n" );
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document.write( "    They want you solve this system for A and B.\r\n" );
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document.write( "2.  Multiply the eqns (1) and (2) by 5 (both sides) to rid of denominators.\r\n" );
document.write( "    Write the system in the canonical form. You will get\r\n" );
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document.write( "     13A +   B =  75,     (1')\r\n" );
document.write( "      -A + 13B = 125.     (2')\r\n" );
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document.write( "3.  Now solve it. You can apply the substitution method by expressing A = 13b - 125 from (2') and substituting it into eqn (1).\r\n" );
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document.write( "From this point please complete the solution on your own.\r\n" );
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