document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89775>Question 89775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 41 years old and his son is 9. In how many years will the father be three times as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65182 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to add some unknown years to both the man's present age and the boy's present<BR>\n" );
document.write( "age. Call that unknown number of years \"x\".<BR>\n" );
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document.write( "In x years, the man will be 41 + x years old and the boy will be 9 + x years old. <BR>\n" );
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document.write( "The problem tells you that at that time the man will be three times as old as the boy.<BR>\n" );
document.write( "In other words, if you multiply the boy's age by 3, the result will equal the man's age.<BR>\n" );
document.write( "In equation form this is:<BR>\n" );
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document.write( "41 + x = 3(9 + x)<BR>\n" );
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document.write( "Multiply out the right side by multiplying 3 times each of the terms in the parentheses.<BR>\n" );
document.write( "When you do that multiplication you get:<BR>\n" );
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document.write( "41 + x = 27 + 3x<BR>\n" );
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document.write( "To solve this equation, you begin by getting all the terms containing x on one side of<BR>\n" );
document.write( "the equation, and then getting all the numbers on the other side. Start by getting rid<BR>\n" );
document.write( "of the x on the left side by subtracting x from both sides.  When you do that subtraction<BR>\n" );
document.write( "you get:<BR>\n" );
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document.write( "41 = 27 + 2x<BR>\n" );
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document.write( "Now get rid of the 27 on the right side by subtracting 27 from both sides to make the<BR>\n" );
document.write( "equation become:<BR>\n" );
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document.write( "14 = 2x<BR>\n" );
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document.write( "Finally, solve for x by dividing both sides by 2:<BR>\n" );
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document.write( "7 = x<BR>\n" );
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document.write( "This tells you that in 7 years the man's age should be 3 times the boy's age.<BR>\n" );
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document.write( "Check:<BR>\n" );
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document.write( "In 7 years the man will be 41 + 7 = 48 years old. And 7 years from now the boy will be<BR>\n" );
document.write( "9 + 7 = 16 years old.  Will the man's age be 3 times the boy's age? Yes it will. So the<BR>\n" );
document.write( "answer of 7 years is correct.<BR>\n" );
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document.write( "Hope this helps you to understand this age problem a little better.<BR>\n" );
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