document.write( "Question 1037022: Hello, can you state the possible number of imaginary zeros for these two functions?\r
\n" ); document.write( "\n" ); document.write( "1. f(x) = ­-x³ ­-x² + 14x - 24\r
\n" ); document.write( "\n" ); document.write( "2. f(x) = 2x³ ­- x² + 16x - 5
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Algebra.Com's Answer #651817 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
For polynomial functions with real coefficients, imaginary zeros come in pairs, so a polynomial function with real coefficients can have 0,2,4, 6,...imaginary zeros.
\n" ); document.write( "However, a polynomial with degree 3 cannot have more than 3 zeros,
\n" ); document.write( "so these functions can have \"highlight%280%29\" or \"highlight%282%29\" imaginary zeros.
\n" ); document.write( "Polynomials of odd degree must have at least 1 real zero.
\n" ); document.write( "They could have 1, 3, 5, all the way up to their degree.
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\n" ); document.write( "NOTE:
\n" ); document.write( "Each of those functions happens to have exactly 1 real zero.
\n" ); document.write( "Some calculus plus calculations (or a graphing calculator) would tell you that.
\n" ); document.write( "Since they are cubic (degree=3) polynomials, they must have a total of 3 zeros,
\n" ); document.write( "so the other \"3-1=2\" zeros are imaginary.
\n" ); document.write( "You are probably not expected to be able to reach that conclusion, though.
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