document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037023>Question 1037023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The one-to-one functions g and h are defined as follows. g={(-7,-6), (-5,4), (4,-7)(7,6)} h(x)= 3x-14 Find the following. g^-1(4)= h^-1(x)= (h^-1 o h)(7)=  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651779 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The one-to-one functions g and h are defined as follows.<BR>\n" );
document.write( " g={(-7,-6), (-5,4), (4,-7), (7,6)} h(x)= 3x-14 ; h^-1(x) = (x+14)/3<BR>\n" );
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document.write( "Find the following. <BR>\n" );
document.write( "g^-1(4)= -5<BR>\n" );
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document.write( "h^-1(x) = (x/3) + (14/3)<BR>\n" );
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document.write( "(h^-1 o h)(7)= 7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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