document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037077>Question 1037077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate the surface area of a triangular prism. The base is 19cm, the length is 22cm and the height is 14cm.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651775 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "With regard to the two triangular faces<BR>\n" );
document.write( "either end of the prism. The hypotenuse <BR>\n" );
document.write( "= &#8730; 14^2 + 19^2<BR>\n" );
document.write( "= 23.6cm.<BR>\n" );
document.write( "Now you have 5 faces:-<BR>\n" );
document.write( "1) Base = 19 x 22 = 418 cm^2<BR>\n" );
document.write( "2) Upright back = 14 x 22 = 308 cm^2<BR>\n" );
document.write( "3) Slanted face = 23.6 x 22 = 519.2 cm^2<BR>\n" );
document.write( "4) 2 triangular ends<BR>\n" );
document.write( "= 1/2(19 x 14) x 2<BR>\n" );
document.write( "= 266 cm^2<BR>\n" );
document.write( "Added together:<BR>\n" );
document.write( "418 + 308 + 519.2 + 266<BR>\n" );
document.write( "= 1511.2 cm^2<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );