document.write( "Question 1037010: Rewrite without rational exponents and simplify if possible\r
\n" ); document.write( "\n" ); document.write( "(5a^2b)^3/5
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Algebra.Com's Answer #651767 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i translate this to read:\r
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\n" ); document.write( "\n" ); document.write( "\"%285%2Aa%5E2%2Ab%29%5E%283%2F5%29\"\r
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\n" ); document.write( "\n" ); document.write( "this is equivalent to\"%28%285%2Aa%5E2%2Ab%29%5E3%29%5E%281%2F5%29\" which is equivalent to \"%285%5E3%2A%28a%5E2%29%5E3%2Ab%5E3%29%5E%281%2F5%29\" which is equivalent to \"%28125%2Aa%5E6%2Ab%5E3%29%5E%281%2F5%29\" which is equivalent to the fifth root of \"%28125%2Aa%5E6%2Ab%5E3%29\".\r
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\n" ); document.write( "\n" ); document.write( "i confirmed by assigning the value of 7 to a and the value of 9 to b and evaluated the original expression and the final expression.\r
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\n" ); document.write( "\n" ); document.write( "i got the original expression = 101.4016814
\n" ); document.write( "i got the final expression = 101.4016814\r
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\n" ); document.write( "\n" ); document.write( "since the values are the same, i assumed that the solution is correct.\r
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\n" ); document.write( "\n" ); document.write( "the basic concepts used are:\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%5Eb%29%5Ec\" = \"a%5E%28b%2Ac%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E%28a%2Fb%29\" = \"%28x%5Ea%29%5E%281%2Fb%29\" = the b root of \"%28x%5Ea%29\".\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "\"%282%5E2%29%5E3\" = \"2%5E%282%2A3%29\" = \"2%5E6\" = 64.\r
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\n" ); document.write( "\n" ); document.write( "since 2^2 = 4 and 4^3 = 64, this confirms the concept is correct.\r
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\n" ); document.write( "\n" ); document.write( "also:\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E%284%2F2%29\" = \"%282%5E4%29%5E%281%2F2%29\" = square root of \"%282%5E4%29\" = 4.\r
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\n" ); document.write( "\n" ); document.write( "since 2^4 = 16 and the square root of 16 is equal to 4, this confirms the concept is correct.\r
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