document.write( "Question 1037064: At a baby shower, 15 guests are in attendance and 3 of them are randomly selected to receive a door prize.
\n" ); document.write( "Question: If all 5 prizes are different, in how many ways can the prizes be awarded?
\n" ); document.write( "I came up with 5x5x5=125 or 5^3 am I doing this right?
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Algebra.Com's Answer #651760 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
probably not.\r
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\n" ); document.write( "\n" ); document.write( "5 prizes being given to 3 people.\r
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\n" ); document.write( "\n" ); document.write( "presumably each person will be given only 1 prize.\r
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\n" ); document.write( "\n" ); document.write( "in that case, then 5C3 sound like the correct formula.\r
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\n" ); document.write( "\n" ); document.write( "5C3 = 5! / (3! * 2!) = (5*4*3!) / (3!*2!) = (5*4)/2!= (5*4)/2 = 10.\r
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\n" ); document.write( "\n" ); document.write( "there are 10 ways that 3 people can each receive 1 out of 5 possible prizes.\r
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\n" ); document.write( "\n" ); document.write( "let's assume the prizes are a,b,c,d,e.
\n" ); document.write( "that's 5 in total.
\n" ); document.write( "1 prize will be given to each of 3 people.
\n" ); document.write( "the possible ways that each of 3 people can receive the prizes would be:\r
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\n" ); document.write( "\n" ); document.write( "a,b,c
\n" ); document.write( "a,b,d
\n" ); document.write( "a,b,e
\n" ); document.write( "a,c,d
\n" ); document.write( "a,c,e
\n" ); document.write( "a,d,e
\n" ); document.write( "b,c,d
\n" ); document.write( "b,c,e
\n" ); document.write( "b,d,e
\n" ); document.write( "c,d,e\r
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\n" ); document.write( "\n" ); document.write( "a,b,c means that person 1 gets a, person 2 gets b, person 3 gets c.
\n" ); document.write( "a,b,d means that person 1 gets a, person 2 gets b, person 3 gets d.
\n" ); document.write( "etc.....\r
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\n" ); document.write( "\n" ); document.write( "5*5*5 doesn't work because then you have the possibility that more than 1 person can get the same prize at the same time, which is impossible.\r
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