document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89733>Question 89733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 56) Number problems.  Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65171 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n+d=50 or n=50-d<BR>\n" );
document.write( "5n+10d=350 now substitute (50-d) for n in this equation & solve for d:<BR>\n" );
document.write( "5(50-d)+10d=350<BR>\n" );
document.write( "250-5d+10d=350<BR>\n" );
document.write( "5d=350-250<BR>\n" );
document.write( "5d=100<BR>\n" );
document.write( "d=20 number of dimes.<BR>\n" );
document.write( "50-20=30 number of nickles.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "5*30=10*20=350<BR>\n" );
document.write( "150+200=350<BR>\n" );
document.write( "350=350 </SPAN>\n" );
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