document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1037005>Question 1037005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide 180 in two parts such that the first part is 12 less than twice the second part. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651704 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the second part be n. Then the first part is 2n-12;<BR>\n" );
document.write( "n+2n-12=180<BR>\n" );
document.write( "3n=192<BR>\n" );
document.write( "n=64<BR>\n" );
document.write( "2n-12=116<BR>\n" );
document.write( "The first part is 116, the second is 64!!!!!!!!!!<BR>\n" );
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