document.write( "Question 1036929: Question#1:
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document.write( "Find the exact value of each of the following. (Hint: you may need Angle Sum/Difference, Double Angle, or Half Angle Identities):\r
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document.write( "a. cos(13pi/12)\r
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document.write( "b. sin(pi/8)\r
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document.write( "c. tan(2X) if cosX = 5/6 and X is in Quadrant 1 \n" );
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Algebra.Com's Answer #651639 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the exact value of each of the following. (Hint: you may need Angle Sum/Difference, Double Angle, or Half Angle Identities): \n" ); document.write( "a. cos(13pi/12) = cos[(3pi/4 + (pi/3)] = cos(3pi/4)cos(pi/3)-sin(3pi/4)sin(pi/3) \n" ); document.write( "= (-sqrt(2)/2)(1/2)) - (sqrt(2)/2)(sqrt(3)/2) \n" ); document.write( "etc. \n" ); document.write( "------\r \n" ); document.write( "\n" ); document.write( "b. sin(pi/8) = sin[(pi/4)/2] = sqrt[(1-cos(pi/4))/2] = sqrt[1-(sqrt(2)/2))/2] \n" ); document.write( "= sqrt[(2-sqrt(2))/4] = sqrt[(1/2) - sqrt(2)/4] \r \n" ); document.write( "\n" ); document.write( "c. tan(2t) if cos(t) = 5/6 and t is in Quadrant 1 \n" ); document.write( "cos = x/r, so x= 5 and r = 6 \n" ); document.write( "then y = sqrt[6^2-5^2] = sqrt(11) \n" ); document.write( "Therefore tan(t) = y/x = sqrt(11)/5 \n" ); document.write( "===== \n" ); document.write( "tan(2t) = sqrt[2tan(t)/(1-tan^2(t)] = sqrt[(2sqrt(11)/5)/(1-(11/25))] \n" ); document.write( "etc. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |